■解答
問１ \(\displaystyle\frac{P_0V_0}{P_0S+Mg}\) 問２ \(\displaystyle\frac{T_0}{T_1}･\frac{P_0V_0}{PS+Mg}\)
問３ \(W_{BC}=\displaystyle\frac{T_1-T_0}{T_0}P_0V_0\) \(Q_{BC}=\displaystyle\frac{5}{2}W_{BC}\)
問４ \(\displaystyle\frac{T_1-T_0}{T_0}･\frac{P_0S}{Mg}\)
問５ 略
■解説
問１
